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1331001603331 = 5921033370147
BaseRepresentation
bin10011010111100101111…
…000001011010100000011
311201020112210100002001221
4103113211320023110003
5133301342402301311
62455241555335511
7165106313646511
oct23274570132403
94636483302057
101331001603331
11473524784674
12195b598b1597
1398688b3b41a
14485c6a3b4b1
152495094a671
hex135e5e0b503

1331001603331 has 12 divisors (see below), whose sum is σ = 1355257666312. Its totient is φ = 1307172079584.

The previous prime is 1331001603293. The next prime is 1331001603361. The reversal of 1331001603331 is 1333061001331.

It is not a de Polignac number, because 1331001603331 - 213 = 1331001595139 is a prime.

It is a super-2 number, since 2×13310016033312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331001603296 and 1331001603305.

It is not an unprimeable number, because it can be changed into a prime (1331001603361) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3410800 + ... + 3780946.

Almost surely, 21331001603331 is an apocalyptic number.

1331001603331 is a deficient number, since it is larger than the sum of its proper divisors (24256062981).

1331001603331 is an equidigital number, since it uses as much as digits as its factorization.

1331001603331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371298 (or 371239 counting only the distinct ones).

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1331001603331 its reverse (1333061001331), we get a palindrome (2664062604662).

The spelling of 1331001603331 in words is "one trillion, three hundred thirty-one billion, one million, six hundred three thousand, three hundred thirty-one".

Divisors: 1 59 1033 3481 60947 370147 3595873 21838673 382361851 1288481707 22559349209 1331001603331