Base | Representation |
---|---|
bin | 10011010111100101111… |
… | …000001011010100000011 |
3 | 11201020112210100002001221 |
4 | 103113211320023110003 |
5 | 133301342402301311 |
6 | 2455241555335511 |
7 | 165106313646511 |
oct | 23274570132403 |
9 | 4636483302057 |
10 | 1331001603331 |
11 | 473524784674 |
12 | 195b598b1597 |
13 | 98688b3b41a |
14 | 485c6a3b4b1 |
15 | 2495094a671 |
hex | 135e5e0b503 |
1331001603331 has 12 divisors (see below), whose sum is σ = 1355257666312. Its totient is φ = 1307172079584.
The previous prime is 1331001603293. The next prime is 1331001603361. The reversal of 1331001603331 is 1333061001331.
It is not a de Polignac number, because 1331001603331 - 213 = 1331001595139 is a prime.
It is a super-2 number, since 2×13310016033312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1331001603296 and 1331001603305.
It is not an unprimeable number, because it can be changed into a prime (1331001603361) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3410800 + ... + 3780946.
Almost surely, 21331001603331 is an apocalyptic number.
1331001603331 is a deficient number, since it is larger than the sum of its proper divisors (24256062981).
1331001603331 is an equidigital number, since it uses as much as digits as its factorization.
1331001603331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 371298 (or 371239 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1331001603331 its reverse (1333061001331), we get a palindrome (2664062604662).
The spelling of 1331001603331 in words is "one trillion, three hundred thirty-one billion, one million, six hundred three thousand, three hundred thirty-one".
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