13310022011113 has 4 divisors (see below), whose sum is σ = 13439245525888. Its totient is φ = 13180798496340.

The previous prime is 13310022011009. The next prime is 13310022011177. The reversal of 13310022011113 is 31111022001331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13310022011113 - 2²⁹ = 13309485140201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13310022011513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64611757233 + ... + 64611757438.

It is an arithmetic number, because the mean of its divisors is an integer number (3359811381472).

Almost surely, 2^{13310022011113} is an apocalyptic number.

It is an amenable number.

13310022011113 is a deficient number, since it is larger than the sum of its proper divisors (129223514775).

13310022011113 is a wasteful number, since it uses less digits than its factorization.

13310022011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129223514774.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13310022011113 its reverse (31111022001331), we get a palindrome (44421044012444).

The spelling of 13310022011113 in words is "thirteen trillion, three hundred ten billion, twenty-two million, eleven thousand, one hundred thirteen".