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13310031310211 = 21616159200051
BaseRepresentation
bin1100000110101111101110…
…1100000010110110000011
31202010102111222002220200102
43001223323230002312003
53221032421003411321
644150313255313015
72542421661302306
oct301537354026603
952112458086612
1013310031310211
114271830756909
1215ab6a667b76b
13757190b1792c
143402cd51ab3d
1518135783ac0b
hexc1afbb02d83

13310031310211 has 4 divisors (see below), whose sum is σ = 13316190512424. Its totient is φ = 13303872108000.

The previous prime is 13310031310171. The next prime is 13310031310223. The reversal of 13310031310211 is 11201313001331.

13310031310211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13310031310211 - 210 = 13310031309187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13310031310241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3079597865 + ... + 3079602186.

It is an arithmetic number, because the mean of its divisors is an integer number (3329047628106).

Almost surely, 213310031310211 is an apocalyptic number.

13310031310211 is a deficient number, since it is larger than the sum of its proper divisors (6159202213).

13310031310211 is an equidigital number, since it uses as much as digits as its factorization.

13310031310211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6159202212.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 13310031310211 its reverse (11201313001331), we get a palindrome (24511344311542).

The spelling of 13310031310211 in words is "thirteen trillion, three hundred ten billion, thirty-one million, three hundred ten thousand, two hundred eleven".

Divisors: 1 2161 6159200051 13310031310211