Base | Representation |
---|---|
bin | 1100000110101111101110… |
… | …1100000010110110000011 |
3 | 1202010102111222002220200102 |
4 | 3001223323230002312003 |
5 | 3221032421003411321 |
6 | 44150313255313015 |
7 | 2542421661302306 |
oct | 301537354026603 |
9 | 52112458086612 |
10 | 13310031310211 |
11 | 4271830756909 |
12 | 15ab6a667b76b |
13 | 757190b1792c |
14 | 3402cd51ab3d |
15 | 18135783ac0b |
hex | c1afbb02d83 |
13310031310211 has 4 divisors (see below), whose sum is σ = 13316190512424. Its totient is φ = 13303872108000.
The previous prime is 13310031310171. The next prime is 13310031310223. The reversal of 13310031310211 is 11201313001331.
13310031310211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13310031310211 - 210 = 13310031309187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13310031310241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3079597865 + ... + 3079602186.
It is an arithmetic number, because the mean of its divisors is an integer number (3329047628106).
Almost surely, 213310031310211 is an apocalyptic number.
13310031310211 is a deficient number, since it is larger than the sum of its proper divisors (6159202213).
13310031310211 is an equidigital number, since it uses as much as digits as its factorization.
13310031310211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6159202212.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 13310031310211 its reverse (11201313001331), we get a palindrome (24511344311542).
The spelling of 13310031310211 in words is "thirteen trillion, three hundred ten billion, thirty-one million, three hundred ten thousand, two hundred eleven".
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