Base | Representation |
---|---|
bin | 111101111110101110… |
… | …1010010011000110001 |
3 | 110201120001122020100121 |
4 | 1323331131102120301 |
5 | 4140042420111032 |
6 | 141051303250241 |
7 | 12421242440443 |
oct | 1737535223061 |
9 | 421501566317 |
10 | 133101332017 |
11 | 514a2260845 |
12 | 21967449981 |
13 | c722577c34 |
14 | 662932c493 |
15 | 36e0271a97 |
hex | 1efd752631 |
133101332017 has 2 divisors, whose sum is σ = 133101332018. Its totient is φ = 133101332016.
The previous prime is 133101332009. The next prime is 133101332027. The reversal of 133101332017 is 710233101331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 66851205136 + 66250126881 = 258556^2 + 257391^2 .
It is a cyclic number.
It is not a de Polignac number, because 133101332017 - 23 = 133101332009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133101331982 and 133101332000.
It is not a weakly prime, because it can be changed into another prime (133101332027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550666008 + 66550666009.
It is an arithmetic number, because the mean of its divisors is an integer number (66550666009).
Almost surely, 2133101332017 is an apocalyptic number.
It is an amenable number.
133101332017 is a deficient number, since it is larger than the sum of its proper divisors (1).
133101332017 is an equidigital number, since it uses as much as digits as its factorization.
133101332017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 133101332017 its reverse (710233101331), we get a palindrome (843334433348).
The spelling of 133101332017 in words is "one hundred thirty-three billion, one hundred one million, three hundred thirty-two thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •