13310141231011 has 2 divisors, whose sum is σ = 13310141231012. Its totient is φ = 13310141231010.

The previous prime is 13310141230993. The next prime is 13310141231021. The reversal of 13310141231011 is 11013214101331.

13310141231011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13310141231011 is a prime.

It is a super-3 number, since 3×13310141231011³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13310141231021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655070615505 + 6655070615506.

It is an arithmetic number, because the mean of its divisors is an integer number (6655070615506).

Almost surely, 2^{13310141231011} is an apocalyptic number.

13310141231011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310141231011 is an equidigital number, since it uses as much as digits as its factorization.

13310141231011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 13310141231011 its reverse (11013214101331), we get a palindrome (24323355332342).

The spelling of 13310141231011 in words is "thirteen trillion, three hundred ten billion, one hundred forty-one million, two hundred thirty-one thousand, eleven".