Base | Representation |
---|---|
bin | 1100000110110000001001… |
… | …0111010011100001010011 |
3 | 1202010102210202212022000000 |
4 | 3001230002113103201103 |
5 | 3221033133142022003 |
6 | 44150332340101043 |
7 | 2542424521311054 |
oct | 301540227234123 |
9 | 52112722768000 |
10 | 13310143314003 |
11 | 42718889a6a28 |
12 | 15ab718094783 |
13 | 7571ab0a2073 |
14 | 34030035472b |
15 | 1813625b21a3 |
hex | c1b025d3853 |
13310143314003 has 56 divisors (see below), whose sum is σ = 20022453296640. Its totient is φ = 8843945750640.
The previous prime is 13310143313993. The next prime is 13310143314049. The reversal of 13310143314003 is 30041334101331.
13310143314003 is a `hidden beast` number, since 1 + 3 + 310 + 14 + 331 + 4 + 0 + 0 + 3 = 666.
It is not a de Polignac number, because 13310143314003 - 237 = 13172704360531 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (13310143314203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 524194438 + ... + 524219828.
Almost surely, 213310143314003 is an apocalyptic number.
13310143314003 is a deficient number, since it is larger than the sum of its proper divisors (6712309982637).
13310143314003 is an equidigital number, since it uses as much as digits as its factorization.
13310143314003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27771 (or 27756 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 13310143314003 its reverse (30041334101331), we get a palindrome (43351477415334).
The spelling of 13310143314003 in words is "thirteen trillion, three hundred ten billion, one hundred forty-three million, three hundred fourteen thousand, three".
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