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13172704360531 is a prime number
BaseRepresentation
bin1011111110110000001001…
…0111010011100001010011
31201122022001102020001121221
42333230002113103201103
53211310144304014111
644003242402225511
72526460615423522
oct277540227234123
951568042201557
1013172704360531
114219570221a71
121588b60055297
13747246c94921
143377c2d084b9
1517c9bb629371
hexbfb025d3853

13172704360531 has 2 divisors, whose sum is σ = 13172704360532. Its totient is φ = 13172704360530.

The previous prime is 13172704360499. The next prime is 13172704360537. The reversal of 13172704360531 is 13506340727131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13172704360531 - 25 = 13172704360499 is a prime.

It is a super-2 number, since 2×131727043605312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13172704360537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6586352180265 + 6586352180266.

It is an arithmetic number, because the mean of its divisors is an integer number (6586352180266).

Almost surely, 213172704360531 is an apocalyptic number.

13172704360531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13172704360531 is an equidigital number, since it uses as much as digits as its factorization.

13172704360531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 317520, while the sum is 43.

The spelling of 13172704360531 in words is "thirteen trillion, one hundred seventy-two billion, seven hundred four million, three hundred sixty thousand, five hundred thirty-one".