Base | Representation |
---|---|
bin | 10011010111100110101… |
… | …111100100111110010001 |
3 | 11201020120210122220220122 |
4 | 103113212233210332101 |
5 | 133301410112020403 |
6 | 2455243234520025 |
7 | 165106551254624 |
oct | 23274657447621 |
9 | 4636523586818 |
10 | 1331016126353 |
11 | 4735319a3a71 |
12 | 195b62736015 |
13 | 9868bb54924 |
14 | 485c893bdbb |
15 | 24951d68838 |
hex | 135e6be4f91 |
1331016126353 has 2 divisors, whose sum is σ = 1331016126354. Its totient is φ = 1331016126352.
The previous prime is 1331016126313. The next prime is 1331016126367. The reversal of 1331016126353 is 3536216101331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1198823528464 + 132192597889 = 1094908^2 + 363583^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331016126353 - 212 = 1331016122257 is a prime.
It is a super-2 number, since 2×13310161263532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1331016126313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665508063176 + 665508063177.
It is an arithmetic number, because the mean of its divisors is an integer number (665508063177).
Almost surely, 21331016126353 is an apocalyptic number.
It is an amenable number.
1331016126353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331016126353 is an equidigital number, since it uses as much as digits as its factorization.
1331016126353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 35.
The spelling of 1331016126353 in words is "one trillion, three hundred thirty-one billion, sixteen million, one hundred twenty-six thousand, three hundred fifty-three".
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