13310203100113 has 2 divisors, whose sum is σ = 13310203100114. Its totient is φ = 13310203100112.

The previous prime is 13310203100071. The next prime is 13310203100119. The reversal of 13310203100113 is 31100130201331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9587649610449 + 3722553489664 = 3096393^2 + 1929392^2 .

It is an emirp because it is prime and its reverse (31100130201331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13310203100113 is a prime.

It is a super-2 number, since 2×13310203100113² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13310203100119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655101550056 + 6655101550057.

It is an arithmetic number, because the mean of its divisors is an integer number (6655101550057).

Almost surely, 2^{13310203100113} is an apocalyptic number.

It is an amenable number.

13310203100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310203100113 is an equidigital number, since it uses as much as digits as its factorization.

13310203100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13310203100113 its reverse (31100130201331), we get a palindrome (44410333301444).

The spelling of 13310203100113 in words is "thirteen trillion, three hundred ten billion, two hundred three million, one hundred thousand, one hundred thirteen".