Base | Representation |
---|---|
bin | 1100000110110000011001… |
… | …1101010101010011101011 |
3 | 1202010102222120010001122211 |
4 | 3001230012131111103223 |
5 | 3221033303233044201 |
6 | 44150343232225551 |
7 | 2542426314204505 |
oct | 301540635252353 |
9 | 52112876101584 |
10 | 13310212003051 |
11 | 4271913752037 |
12 | 15ab73709b2b7 |
13 | 7571bc3a1c82 |
14 | 340309514d75 |
15 | 18136862e651 |
hex | c1b067554eb |
13310212003051 has 2 divisors, whose sum is σ = 13310212003052. Its totient is φ = 13310212003050.
The previous prime is 13310212003013. The next prime is 13310212003069. The reversal of 13310212003051 is 15030021201331.
13310212003051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (15030021201331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13310212003051 - 223 = 13310203614443 is a prime.
It is not a weakly prime, because it can be changed into another prime (13310212004051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655106001525 + 6655106001526.
It is an arithmetic number, because the mean of its divisors is an integer number (6655106001526).
Almost surely, 213310212003051 is an apocalyptic number.
13310212003051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310212003051 is an equidigital number, since it uses as much as digits as its factorization.
13310212003051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13310212003051 its reverse (15030021201331), we get a palindrome (28340233204382).
The spelling of 13310212003051 in words is "thirteen trillion, three hundred ten billion, two hundred twelve million, three thousand, fifty-one".
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