Base | Representation |
---|---|
bin | 1100000110110000011010… |
… | …0001100110000011011111 |
3 | 1202010102222122012211010120 |
4 | 3001230012201212003133 |
5 | 3221033304024321343 |
6 | 44150343312210023 |
7 | 2542426326536535 |
oct | 301540641460337 |
9 | 52112878184116 |
10 | 13310213120223 |
11 | 4271914345418 |
12 | 15ab737539913 |
13 | 7571bc6a3616 |
14 | 340309726155 |
15 | 1813687a0683 |
hex | c1b068660df |
13310213120223 has 16 divisors (see below), whose sum is σ = 17946556704000. Its totient is φ = 8773674719040.
The previous prime is 13310213120221. The next prime is 13310213120231. The reversal of 13310213120223 is 32202131201331.
It is not a de Polignac number, because 13310213120223 - 21 = 13310213120221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13310213120193 and 13310213120202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13310213120221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29340078 + ... + 29790276.
It is an arithmetic number, because the mean of its divisors is an integer number (1121659794000).
Almost surely, 213310213120223 is an apocalyptic number.
13310213120223 is a deficient number, since it is larger than the sum of its proper divisors (4636343583777).
13310213120223 is a wasteful number, since it uses less digits than its factorization.
13310213120223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 561022.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13310213120223 its reverse (32202131201331), we get a palindrome (45512344321554).
The spelling of 13310213120223 in words is "thirteen trillion, three hundred ten billion, two hundred thirteen million, one hundred twenty thousand, two hundred twenty-three".
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