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1331024314241 is a prime number
BaseRepresentation
bin10011010111100111001…
…110110011111110000001
311201020121101001220120202
4103113213032303332001
5133301414211023431
62455244130214545
7165110010666206
oct23274716637601
94636541056522
101331024314241
11473536586716
12195b65424455
139869076072b
14485c9a6dcad
15249529348cb
hex135e73b3f81

1331024314241 has 2 divisors, whose sum is σ = 1331024314242. Its totient is φ = 1331024314240.

The previous prime is 1331024314219. The next prime is 1331024314253. The reversal of 1331024314241 is 1424134201331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1212410199025 + 118614115216 = 1101095^2 + 344404^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331024314241 - 218 = 1331024052097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1331024394241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665512157120 + 665512157121.

It is an arithmetic number, because the mean of its divisors is an integer number (665512157121).

Almost surely, 21331024314241 is an apocalyptic number.

It is an amenable number.

1331024314241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331024314241 is an equidigital number, since it uses as much as digits as its factorization.

1331024314241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1331024314241 its reverse (1424134201331), we get a palindrome (2755158515572).

The spelling of 1331024314241 in words is "one trillion, three hundred thirty-one billion, twenty-four million, three hundred fourteen thousand, two hundred forty-one".