Search a number
-
+
133103102112000 = 283253479833267
BaseRepresentation
bin11110010000111001111011…
…000111101011000100000000
3122110021112101001002112010200
4132100321323013223010000
5114421230123120041000
61151030415421325200
740015244644356426
oct3620717307530400
9573245331075120
10133103102112000
1139457788173729
1212b18333706800
1359367514abc47
1424c23200dd116
15105c4b553b500
hex790e7b1eb100

133103102112000 has 432 divisors, whose sum is σ = 489134126138112. Its totient is φ = 34738962124800.

The previous prime is 133103102111999. The next prime is 133103102112109. The reversal of 133103102112000 is 211201301331.

133103102112000 is a `hidden beast` number, since 1 + 3 + 310 + 310 + 21 + 1 + 20 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8619367 + ... + 18452633.

It is an arithmetic number, because the mean of its divisors is an integer number (1132254921616).

Almost surely, 2133103102112000 is an apocalyptic number.

133103102112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133103102112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (244567063069056).

133103102112000 is an abundant number, since it is smaller than the sum of its proper divisors (356031024026112).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133103102112000 is an equidigital number, since it uses as much as digits as its factorization.

133103102112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9833351 (or 9833324 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 133103102112000 its reverse (211201301331), we get a palindrome (133314303413331).

The spelling of 133103102112000 in words is "one hundred thirty-three trillion, one hundred three billion, one hundred two million, one hundred twelve thousand".