Base | Representation |
---|---|
bin | 11110010000111010000010… |
… | …110000110010110011010001 |
3 | 122110021112200222100210001202 |
4 | 132100322002300302303101 |
5 | 114421230403431111423 |
6 | 1151030440241440545 |
7 | 40015251062255126 |
oct | 3620720260626321 |
9 | 573245628323052 |
10 | 133103230332113 |
11 | 3945784358a368 |
12 | 12b1836a640155 |
13 | 5936771c23532 |
14 | 24c233315874d |
15 | 105c4c1917728 |
hex | 790e82c32cd1 |
133103230332113 has 2 divisors, whose sum is σ = 133103230332114. Its totient is φ = 133103230332112.
The previous prime is 133103230332101. The next prime is 133103230332161. The reversal of 133103230332113 is 311233032301331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117338463314944 + 15764767017169 = 10832288^2 + 3970487^2 .
It is a cyclic number.
It is not a de Polignac number, because 133103230332113 - 234 = 133086050462929 is a prime.
It is not a weakly prime, because it can be changed into another prime (133103230332013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66551615166056 + 66551615166057.
It is an arithmetic number, because the mean of its divisors is an integer number (66551615166057).
Almost surely, 2133103230332113 is an apocalyptic number.
It is an amenable number.
133103230332113 is a deficient number, since it is larger than the sum of its proper divisors (1).
133103230332113 is an equidigital number, since it uses as much as digits as its factorization.
133103230332113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8748, while the sum is 29.
Adding to 133103230332113 its reverse (311233032301331), we get a palindrome (444336262633444).
The spelling of 133103230332113 in words is "one hundred thirty-three trillion, one hundred three billion, two hundred thirty million, three hundred thirty-two thousand, one hundred thirteen".
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