Base | Representation |
---|---|
bin | 1100000110110001000111… |
… | …1001110111001110111001 |
3 | 1202010110110221110010001112 |
4 | 3001230101321313032321 |
5 | 3221034201413001132 |
6 | 44150414252130105 |
7 | 2542434135341123 |
oct | 301542171671671 |
9 | 52113427403045 |
10 | 13310404031417 |
11 | 4271a0208a869 |
12 | 15ab78b466935 |
13 | 7572200c7a1c |
14 | 340326c20213 |
15 | 18137a411ab2 |
hex | c1b11e773b9 |
13310404031417 has 2 divisors, whose sum is σ = 13310404031418. Its totient is φ = 13310404031416.
The previous prime is 13310404031339. The next prime is 13310404031467. The reversal of 13310404031417 is 71413040401331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12310302028816 + 1000102002601 = 3508604^2 + 1000051^2 .
It is a cyclic number.
It is not a de Polignac number, because 13310404031417 - 28 = 13310404031161 is a prime.
It is not a weakly prime, because it can be changed into another prime (13310404031467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655202015708 + 6655202015709.
It is an arithmetic number, because the mean of its divisors is an integer number (6655202015709).
Almost surely, 213310404031417 is an apocalyptic number.
It is an amenable number.
13310404031417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13310404031417 is an equidigital number, since it uses as much as digits as its factorization.
13310404031417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13310404031417 its reverse (71413040401331), we get a palindrome (84723444432748).
The spelling of 13310404031417 in words is "thirteen trillion, three hundred ten billion, four hundred four million, thirty-one thousand, four hundred seventeen".
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