Base | Representation |
---|---|
bin | 111101111110110011… |
… | …1100111110011010011 |
3 | 110201120020201212121122 |
4 | 1323331213213303103 |
5 | 4140044113304141 |
6 | 141051441312455 |
7 | 12421304453033 |
oct | 1737547476323 |
9 | 421506655548 |
10 | 133104041171 |
11 | 514a3841212 |
12 | 2196833572b |
13 | c722cb609a |
14 | 66298358c3 |
15 | 36e060964b |
hex | 1efd9e7cd3 |
133104041171 has 2 divisors, whose sum is σ = 133104041172. Its totient is φ = 133104041170.
The previous prime is 133104041111. The next prime is 133104041179. The reversal of 133104041171 is 171140401331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133104041171 - 218 = 133103779027 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133104041171.
It is not a weakly prime, because it can be changed into another prime (133104041179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66552020585 + 66552020586.
It is an arithmetic number, because the mean of its divisors is an integer number (66552020586).
Almost surely, 2133104041171 is an apocalyptic number.
133104041171 is a deficient number, since it is larger than the sum of its proper divisors (1).
133104041171 is an equidigital number, since it uses as much as digits as its factorization.
133104041171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
The spelling of 133104041171 in words is "one hundred thirty-three billion, one hundred four million, forty-one thousand, one hundred seventy-one".
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