Base | Representation |
---|---|
bin | 1100000110110011110010… |
… | …0101100010000011111011 |
3 | 1202010112022211220021210221 |
4 | 3001230330211202003323 |
5 | 3221042133222401412 |
6 | 44151013312320511 |
7 | 2542460652120103 |
oct | 301547445420373 |
9 | 52115284807727 |
10 | 13311120122107 |
11 | 427223a31a355 |
12 | 15ab94b243137 |
13 | 75730557c022 |
14 | 340393d86203 |
15 | 1813bd211b07 |
hex | c1b3c9620fb |
13311120122107 has 2 divisors, whose sum is σ = 13311120122108. Its totient is φ = 13311120122106.
The previous prime is 13311120122087. The next prime is 13311120122117. The reversal of 13311120122107 is 70122102111331.
13311120122107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311120122107 - 219 = 13311119597819 is a prime.
It is not a weakly prime, because it can be changed into another prime (13311120122117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655560061053 + 6655560061054.
It is an arithmetic number, because the mean of its divisors is an integer number (6655560061054).
Almost surely, 213311120122107 is an apocalyptic number.
13311120122107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311120122107 is an equidigital number, since it uses as much as digits as its factorization.
13311120122107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 13311120122107 its reverse (70122102111331), we get a palindrome (83433222233438).
The spelling of 13311120122107 in words is "thirteen trillion, three hundred eleven billion, one hundred twenty million, one hundred twenty-two thousand, one hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •