13311124414201 has 4 divisors (see below), whose sum is σ = 13339627893072. Its totient is φ = 13282620935332.

The previous prime is 13311124414151. The next prime is 13311124414223. The reversal of 13311124414201 is 10241442111331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13311124414201 - 2³³ = 13302534479609 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13311124414201.

It is not an unprimeable number, because it can be changed into a prime (13311124414261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14251738735 + ... + 14251739668.

It is an arithmetic number, because the mean of its divisors is an integer number (3334906973268).

Almost surely, 2^{13311124414201} is an apocalyptic number.

It is an amenable number.

13311124414201 is a deficient number, since it is larger than the sum of its proper divisors (28503478871).

13311124414201 is an equidigital number, since it uses as much as digits as its factorization.

13311124414201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28503478870.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 13311124414201 its reverse (10241442111331), we get a palindrome (23552566525532).

The spelling of 13311124414201 in words is "thirteen trillion, three hundred eleven billion, one hundred twenty-four million, four hundred fourteen thousand, two hundred one".