Base | Representation |
---|---|
bin | 10011010111101100100… |
… | …100111100001101001011 |
3 | 11201020211121211110222222 |
4 | 103113230210330031023 |
5 | 133302110141014402 |
6 | 2455301052404255 |
7 | 165112150216253 |
oct | 23275444741513 |
9 | 4636747743888 |
10 | 1331114001227 |
11 | 47358217389a |
12 | 195b8b47668b |
13 | 986a620305a |
14 | 485d7938963 |
15 | 2495a74d7a2 |
hex | 135ec93c34b |
1331114001227 has 2 divisors, whose sum is σ = 1331114001228. Its totient is φ = 1331114001226.
The previous prime is 1331114001211. The next prime is 1331114001257. The reversal of 1331114001227 is 7221004111331.
It is a weak prime.
It is an emirp because it is prime and its reverse (7221004111331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1331114001227 - 24 = 1331114001211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1331114001196 and 1331114001205.
It is not a weakly prime, because it can be changed into another prime (1331114001257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665557000613 + 665557000614.
It is an arithmetic number, because the mean of its divisors is an integer number (665557000614).
Almost surely, 21331114001227 is an apocalyptic number.
1331114001227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331114001227 is an equidigital number, since it uses as much as digits as its factorization.
1331114001227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 1331114001227 its reverse (7221004111331), we get a palindrome (8552118112558).
The spelling of 1331114001227 in words is "one trillion, three hundred thirty-one billion, one hundred fourteen million, one thousand, two hundred twenty-seven".
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