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133112020153 = 719016002879
BaseRepresentation
bin111101111111000011…
…0000011110010111001
3110201120210202020201111
41323332012003302321
54140103134121103
6141052324320321
712421432334260
oct1737606036271
9421523666644
10133112020153
11514a82a0a12
122196ab430a1
13c72484aa88
14662a9115d7
1536e118386d
hex1efe183cb9

133112020153 has 4 divisors (see below), whose sum is σ = 152128023040. Its totient is φ = 114096017268.

The previous prime is 133112020109. The next prime is 133112020177. The reversal of 133112020153 is 351020211331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133112020153 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133112020103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9508001433 + ... + 9508001446.

It is an arithmetic number, because the mean of its divisors is an integer number (38032005760).

Almost surely, 2133112020153 is an apocalyptic number.

It is an amenable number.

133112020153 is a deficient number, since it is larger than the sum of its proper divisors (19016002887).

133112020153 is an equidigital number, since it uses as much as digits as its factorization.

133112020153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19016002886.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 133112020153 its reverse (351020211331), we get a palindrome (484132231484).

The spelling of 133112020153 in words is "one hundred thirty-three billion, one hundred twelve million, twenty thousand, one hundred fifty-three".

Divisors: 1 7 19016002879 133112020153