Base | Representation |
---|---|
bin | 1100000110110100000101… |
… | …1110010000101100001011 |
3 | 1202010112112120011022010021 |
4 | 3001231001132100230023 |
5 | 3221042320214231102 |
6 | 44151025401401311 |
7 | 2542462666000444 |
oct | 301550136205413 |
9 | 52115476138107 |
10 | 13311202102027 |
11 | 4272281623055 |
12 | 15ab972799237 |
13 | 75731955365b |
14 | 3403a0c062cb |
15 | 1813c5507137 |
hex | c1b41790b0b |
13311202102027 has 2 divisors, whose sum is σ = 13311202102028. Its totient is φ = 13311202102026.
The previous prime is 13311202102021. The next prime is 13311202102031. The reversal of 13311202102027 is 72020120211331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13311202102027 - 23 = 13311202102019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13311202101992 and 13311202102010.
It is not a weakly prime, because it can be changed into another prime (13311202102021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655601051013 + 6655601051014.
It is an arithmetic number, because the mean of its divisors is an integer number (6655601051014).
Almost surely, 213311202102027 is an apocalyptic number.
13311202102027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311202102027 is an equidigital number, since it uses as much as digits as its factorization.
13311202102027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 13311202102027 its reverse (72020120211331), we get a palindrome (85331322313358).
The spelling of 13311202102027 in words is "thirteen trillion, three hundred eleven billion, two hundred two million, one hundred two thousand, twenty-seven".
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