Base | Representation |
---|---|
bin | 11110010001000010001111… |
… | …011001010011010101111011 |
3 | 122110022101102101122121211222 |
4 | 132101002033121103111323 |
5 | 114421401420221243342 |
6 | 1151034453504342255 |
7 | 40016012151102416 |
oct | 3621021731232573 |
9 | 573271371577758 |
10 | 133112032212347 |
11 | 3946054aa62251 |
12 | 12b1a00631498b |
13 | 59375456272a6 |
14 | 24c292a11ab7d |
15 | 105c83950bed2 |
hex | 79108f65357b |
133112032212347 has 2 divisors, whose sum is σ = 133112032212348. Its totient is φ = 133112032212346.
The previous prime is 133112032212281. The next prime is 133112032212373. The reversal of 133112032212347 is 743212230211331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133112032212347 - 212 = 133112032208251 is a prime.
It is not a weakly prime, because it can be changed into another prime (133112032212647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556016106173 + 66556016106174.
It is an arithmetic number, because the mean of its divisors is an integer number (66556016106174).
Almost surely, 2133112032212347 is an apocalyptic number.
133112032212347 is a deficient number, since it is larger than the sum of its proper divisors (1).
133112032212347 is an equidigital number, since it uses as much as digits as its factorization.
133112032212347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 133112032212347 its reverse (743212230211331), we get a palindrome (876324262423678).
The spelling of 133112032212347 in words is "one hundred thirty-three trillion, one hundred twelve billion, thirty-two million, two hundred twelve thousand, three hundred forty-seven".
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