Base | Representation |
---|---|
bin | 1100000110110100001010… |
… | …1011000011011101101011 |
3 | 1202010112120222001001112121 |
4 | 3001231002223003131223 |
5 | 3221042340342423224 |
6 | 44151031401052111 |
7 | 2542463332053241 |
oct | 301550253033553 |
9 | 52115528031477 |
10 | 13311222232939 |
11 | 4272291a22774 |
12 | 15ab979487037 |
13 | 757320781537 |
14 | 3403a3766791 |
15 | 1813c7181be4 |
hex | c1b42ac376b |
13311222232939 has 2 divisors, whose sum is σ = 13311222232940. Its totient is φ = 13311222232938.
The previous prime is 13311222232933. The next prime is 13311222232981. The reversal of 13311222232939 is 93923222211331.
13311222232939 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13311222232939 - 229 = 13310685362027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13311222232895 and 13311222232904.
It is not a weakly prime, because it can be changed into another prime (13311222232933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655611116469 + 6655611116470.
It is an arithmetic number, because the mean of its divisors is an integer number (6655611116470).
Almost surely, 213311222232939 is an apocalyptic number.
13311222232939 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311222232939 is an equidigital number, since it uses as much as digits as its factorization.
13311222232939 is an evil number, because the sum of its binary digits is even.
The product of its digits is 209952, while the sum is 43.
The spelling of 13311222232939 in words is "thirteen trillion, three hundred eleven billion, two hundred twenty-two million, two hundred thirty-two thousand, nine hundred thirty-nine".
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