Base | Representation |
---|---|
bin | 11110010001000010011111… |
… | …011011000111011000100011 |
3 | 122110022102010010122201001202 |
4 | 132101002133123013120203 |
5 | 114421402443041414412 |
6 | 1151034540312151415 |
7 | 40016021624565665 |
oct | 3621023733073043 |
9 | 573272103581052 |
10 | 133112301123107 |
11 | 39460678831949 |
12 | 12b1a08039856b |
13 | 593758925b397 |
14 | 24c2953b1a535 |
15 | 105c852e293c2 |
hex | 79109f6c7623 |
133112301123107 has 2 divisors, whose sum is σ = 133112301123108. Its totient is φ = 133112301123106.
The previous prime is 133112301123091. The next prime is 133112301123223. The reversal of 133112301123107 is 701321103211331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133112301123107 - 24 = 133112301123091 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133112301123107.
It is not a weakly prime, because it can be changed into another prime (133112301120107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556150561553 + 66556150561554.
It is an arithmetic number, because the mean of its divisors is an integer number (66556150561554).
Almost surely, 2133112301123107 is an apocalyptic number.
133112301123107 is a deficient number, since it is larger than the sum of its proper divisors (1).
133112301123107 is an equidigital number, since it uses as much as digits as its factorization.
133112301123107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 29.
Adding to 133112301123107 its reverse (701321103211331), we get a palindrome (834433404334438).
The spelling of 133112301123107 in words is "one hundred thirty-three trillion, one hundred twelve billion, three hundred one million, one hundred twenty-three thousand, one hundred seven".
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