Base | Representation |
---|---|
bin | 11110010001000010100010… |
… | …101001111100000010100011 |
3 | 122110022102020220200020021112 |
4 | 132101002202221330002203 |
5 | 114421403100431343301 |
6 | 1151034545530213535 |
7 | 40016023153460024 |
oct | 3621024251740243 |
9 | 573272226606245 |
10 | 133112355340451 |
11 | 394606a63a3173 |
12 | 12b1a0965842ab |
13 | 5937597562256 |
14 | 24c295add0c4b |
15 | 105c857a889bb |
hex | 7910a2a7c0a3 |
133112355340451 has 2 divisors, whose sum is σ = 133112355340452. Its totient is φ = 133112355340450.
The previous prime is 133112355340441. The next prime is 133112355340457. The reversal of 133112355340451 is 154043553211331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133112355340451 - 26 = 133112355340387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133112355340399 and 133112355340408.
It is not a weakly prime, because it can be changed into another prime (133112355340457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556177670225 + 66556177670226.
It is an arithmetic number, because the mean of its divisors is an integer number (66556177670226).
Almost surely, 2133112355340451 is an apocalyptic number.
133112355340451 is a deficient number, since it is larger than the sum of its proper divisors (1).
133112355340451 is an equidigital number, since it uses as much as digits as its factorization.
133112355340451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 41.
The spelling of 133112355340451 in words is "one hundred thirty-three trillion, one hundred twelve billion, three hundred fifty-five million, three hundred forty thousand, four hundred fifty-one".
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