13311311330323 has 4 divisors (see below), whose sum is σ = 13311501553768. Its totient is φ = 13311121106880.

The previous prime is 13311311330281. The next prime is 13311311330381. The reversal of 13311311330323 is 32303311311331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13311311330323 - 2²¹ = 13311309233171 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311311330291 and 13311311330300.

It is not an unprimeable number, because it can be changed into a prime (13311315330323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95006718 + ... + 95146723.

It is an arithmetic number, because the mean of its divisors is an integer number (3327875388442).

Almost surely, 2^{13311311330323} is an apocalyptic number.

13311311330323 is a deficient number, since it is larger than the sum of its proper divisors (190223445).

13311311330323 is an equidigital number, since it uses as much as digits as its factorization.

13311311330323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190223444.

The product of its (nonzero) digits is 4374, while the sum is 28.

Adding to 13311311330323 its reverse (32303311311331), we get a palindrome (45614622641654).

The spelling of 13311311330323 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, three hundred thirty thousand, three hundred twenty-three".