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13311341233 = 195569125803
BaseRepresentation
bin11000110010110101…
…01111001010110001
31021100200122012100021
430121122233022301
5204230200404413
610040512123441
7650603351011
oct143132571261
937320565307
1013311341233
1157109a5763
1226b5b36581
131341a40998
14903c51c41
1552d95118d
hex3196af2b1

13311341233 has 8 divisors (see below), whose sum is σ = 14014565600. Its totient is φ = 12608379648.

The previous prime is 13311341231. The next prime is 13311341327. The reversal of 13311341233 is 33214311331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13311341233 - 21 = 13311341231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311341198 and 13311341207.

It is not an unprimeable number, because it can be changed into a prime (13311341231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42910 + ... + 168712.

It is an arithmetic number, because the mean of its divisors is an integer number (1751820700).

Almost surely, 213311341233 is an apocalyptic number.

It is an amenable number.

13311341233 is a deficient number, since it is larger than the sum of its proper divisors (703224367).

13311341233 is a wasteful number, since it uses less digits than its factorization.

13311341233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131391.

The product of its digits is 1944, while the sum is 25.

Adding to 13311341233 its reverse (33214311331), we get a palindrome (46525652564).

The spelling of 13311341233 in words is "thirteen billion, three hundred eleven million, three hundred forty-one thousand, two hundred thirty-three".

Divisors: 1 19 5569 105811 125803 2390257 700596907 13311341233