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133113444040441 is a prime number
BaseRepresentation
bin11110010001000011100011…
…100010111111111011111001
3122110022112001210020220220101
4132101003203202333323321
5114421412313133243231
61151035245540555401
740016062143330334
oct3621034342777371
9573275053226811
10133113444040441
113946110499a627
1212b1a33b0b2b61
13593770bc87727
1424c2a2182b61b
15105c8bd43b661
hex7910e38bfef9

133113444040441 has 2 divisors, whose sum is σ = 133113444040442. Its totient is φ = 133113444040440.

The previous prime is 133113444040429. The next prime is 133113444040463. The reversal of 133113444040441 is 144040444311331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75411508640400 + 57701935400041 = 8683980^2 + 7596179^2 .

It is a cyclic number.

It is not a de Polignac number, because 133113444040441 - 215 = 133113444007673 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133113444040441.

It is not a weakly prime, because it can be changed into another prime (133113444010441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556722020220 + 66556722020221.

It is an arithmetic number, because the mean of its divisors is an integer number (66556722020221).

Almost surely, 2133113444040441 is an apocalyptic number.

It is an amenable number.

133113444040441 is a deficient number, since it is larger than the sum of its proper divisors (1).

133113444040441 is an equidigital number, since it uses as much as digits as its factorization.

133113444040441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 37.

Adding to 133113444040441 its reverse (144040444311331), we get a palindrome (277153888351772).

The spelling of 133113444040441 in words is "one hundred thirty-three trillion, one hundred thirteen billion, four hundred forty-four million, forty thousand, four hundred forty-one".