Base | Representation |
---|---|
bin | 111101111111000111… |
… | …1010010101011111010 |
3 | 110201120222022012201211 |
4 | 1323332033102223322 |
5 | 4140104244043232 |
6 | 141052452233334 |
7 | 12421462034434 |
oct | 1737617225372 |
9 | 421528265654 |
10 | 133114440442 |
11 | 514a96a4355 |
12 | 2196b90b84a |
13 | c7251b75b9 |
14 | 662ad81654 |
15 | 36e14b0a47 |
hex | 1efe3d2afa |
133114440442 has 4 divisors (see below), whose sum is σ = 199671660666. Its totient is φ = 66557220220.
The previous prime is 133114440421. The next prime is 133114440461. The reversal of 133114440442 is 244044411331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 133041833001 + 72607441 = 364749^2 + 8521^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33278610109 + ... + 33278610112.
Almost surely, 2133114440442 is an apocalyptic number.
133114440442 is a deficient number, since it is larger than the sum of its proper divisors (66557220224).
133114440442 is an equidigital number, since it uses as much as digits as its factorization.
133114440442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66557220223.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 133114440442 its reverse (244044411331), we get a palindrome (377158851773).
The spelling of 133114440442 in words is "one hundred thirty-three billion, one hundred fourteen million, four hundred forty thousand, four hundred forty-two".
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