Base | Representation |
---|---|
bin | 11110010001001001111100… |
… | …110110011010111010010011 |
3 | 122110100011210100200021100210 |
4 | 132101021330312122322103 |
5 | 114422020344104404021 |
6 | 1151042343204015203 |
7 | 40016424255536460 |
oct | 3621117466327223 |
9 | 573304710607323 |
10 | 133120311013011 |
11 | 39464009144773 |
12 | 12b1b736991503 |
13 | 5938264854bca |
14 | 24c30b383a667 |
15 | 105cb71229e76 |
hex | 79127cd9ae93 |
133120311013011 has 8 divisors (see below), whose sum is σ = 202849997734144. Its totient is φ = 76068749150280.
The previous prime is 133120311012943. The next prime is 133120311013021. The reversal of 133120311013011 is 110310113021331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133120311013011 - 215 = 133120310980243 is a prime.
It is a super-2 number, since 2×1331203110130112 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 6339062429191 = 133120311013011 / (1 + 3 + 3 + 1 + 2 + 0 + 3 + 1 + 1 + 0 + 1 + 3 + 0 + 1 + 1).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133120311013021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3169531214575 + ... + 3169531214616.
It is an arithmetic number, because the mean of its divisors is an integer number (25356249716768).
Almost surely, 2133120311013011 is an apocalyptic number.
133120311013011 is a deficient number, since it is larger than the sum of its proper divisors (69729686721133).
133120311013011 is an equidigital number, since it uses as much as digits as its factorization.
133120311013011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6339062429201.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 133120311013011 its reverse (110310113021331), we get a palindrome (243430424034342).
The spelling of 133120311013011 in words is "one hundred thirty-three trillion, one hundred twenty billion, three hundred eleven million, thirteen thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •