Base | Representation |
---|---|
bin | 10011010111110010010… |
… | …111011011100100111001 |
3 | 11201021002101120210000201 |
4 | 103113302113123210321 |
5 | 133302310021414001 |
6 | 2455314442202201 |
7 | 165114436563154 |
oct | 23276227334471 |
9 | 4637071523021 |
10 | 1331211123001 |
11 | 473621a79921 |
12 | 195bb7ab3361 |
13 | 986c0379766 |
14 | 486067bac9b |
15 | 24964035501 |
hex | 135f25db939 |
1331211123001 has 2 divisors, whose sum is σ = 1331211123002. Its totient is φ = 1331211123000.
The previous prime is 1331211122929. The next prime is 1331211123019. The reversal of 1331211123001 is 1003211121331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1271653160976 + 59557962025 = 1127676^2 + 244045^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331211123001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1331211123001.
It is not a weakly prime, because it can be changed into another prime (1331211123031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665605561500 + 665605561501.
It is an arithmetic number, because the mean of its divisors is an integer number (665605561501).
Almost surely, 21331211123001 is an apocalyptic number.
It is an amenable number.
1331211123001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331211123001 is an equidigital number, since it uses as much as digits as its factorization.
1331211123001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1331211123001 its reverse (1003211121331), we get a palindrome (2334422244332).
The spelling of 1331211123001 in words is "one trillion, three hundred thirty-one billion, two hundred eleven million, one hundred twenty-three thousand, one".
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