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133121122003 = 961313848031
BaseRepresentation
bin111101111111010100…
…0110001111011010011
3110201121102212200010001
41323332220301323103
54140113001401003
6141053251350431
712421602603262
oct1737650617323
9421542780101
10133121122003
1151502448301
1221971bb2417
13c7266b689c
14662bc005d9
1536e1d8061d
hex1efea31ed3

133121122003 has 4 divisors (see below), whose sum is σ = 133134979648. Its totient is φ = 133107264360.

The previous prime is 133121121929. The next prime is 133121122009. The reversal of 133121122003 is 300221121331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133121122003 is a prime.

It is a super-2 number, since 2×1331211220032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133121122009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6914403 + ... + 6933628.

It is an arithmetic number, because the mean of its divisors is an integer number (33283744912).

Almost surely, 2133121122003 is an apocalyptic number.

133121122003 is a deficient number, since it is larger than the sum of its proper divisors (13857645).

133121122003 is an equidigital number, since it uses as much as digits as its factorization.

133121122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13857644.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 133121122003 its reverse (300221121331), we get a palindrome (433342243334).

The spelling of 133121122003 in words is "one hundred thirty-three billion, one hundred twenty-one million, one hundred twenty-two thousand, three".

Divisors: 1 9613 13848031 133121122003