13312141020241 has 4 divisors (see below), whose sum is σ = 15213875451712. Its totient is φ = 11410406588772.

The previous prime is 13312141020223. The next prime is 13312141020257. The reversal of 13312141020241 is 14202014121331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13312141020241 - 2⁹ = 13312141019729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13312141020221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950867215725 + ... + 950867215738.

It is an arithmetic number, because the mean of its divisors is an integer number (3803468862928).

Almost surely, 2^{13312141020241} is an apocalyptic number.

It is an amenable number.

13312141020241 is a deficient number, since it is larger than the sum of its proper divisors (1901734431471).

13312141020241 is an equidigital number, since it uses as much as digits as its factorization.

13312141020241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1901734431470.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13312141020241 its reverse (14202014121331), we get a palindrome (27514155141572).

The spelling of 13312141020241 in words is "thirteen trillion, three hundred twelve billion, one hundred forty-one million, twenty thousand, two hundred forty-one".