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13312203341081 is a prime number
BaseRepresentation
bin1100000110110111110100…
…1001101011110100011001
31202010122010100011111220012
43001231331021223310121
53221101343023403311
644151313005411305
72542526544251651
oct301557511536431
952118110144805
1013312203341081
114272745812847
1215abbb1b69b35
13757448b057b8
14340457b97361
1518143338078b
hexc1b7d26bd19

13312203341081 has 2 divisors, whose sum is σ = 13312203341082. Its totient is φ = 13312203341080.

The previous prime is 13312203341057. The next prime is 13312203341179. The reversal of 13312203341081 is 18014330221331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6732675667600 + 6579527673481 = 2594740^2 + 2565059^2 .

It is a cyclic number.

It is not a de Polignac number, because 13312203341081 - 214 = 13312203324697 is a prime.

It is a super-3 number, since 3×133122033410813 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13312203301081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656101670540 + 6656101670541.

It is an arithmetic number, because the mean of its divisors is an integer number (6656101670541).

Almost surely, 213312203341081 is an apocalyptic number.

It is an amenable number.

13312203341081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312203341081 is an equidigital number, since it uses as much as digits as its factorization.

13312203341081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 13312203341081 in words is "thirteen trillion, three hundred twelve billion, two hundred three million, three hundred forty-one thousand, eighty-one".