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1331223131401 is a prime number
BaseRepresentation
bin10011010111110011000…
…101001111010100001001
311201021010020011212110021
4103113303011033110021
5133302321110201101
62455315551420441
7165114643626112
oct23276305172411
94637106155407
101331223131401
11473628830a19
12195bbbb24721
13986c29c2517
1448608225209
15249651085a1
hex135f314f509

1331223131401 has 2 divisors, whose sum is σ = 1331223131402. Its totient is φ = 1331223131400.

The previous prime is 1331223131393. The next prime is 1331223131449. The reversal of 1331223131401 is 1041313221331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1304792175625 + 26430955776 = 1142275^2 + 162576^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331223131401 - 23 = 1331223131393 is a prime.

It is a super-2 number, since 2×13312231314012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1331223131701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665611565700 + 665611565701.

It is an arithmetic number, because the mean of its divisors is an integer number (665611565701).

Almost surely, 21331223131401 is an apocalyptic number.

It is an amenable number.

1331223131401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331223131401 is an equidigital number, since it uses as much as digits as its factorization.

1331223131401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1331223131401 its reverse (1041313221331), we get a palindrome (2372536352732).

The spelling of 1331223131401 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-three million, one hundred thirty-one thousand, four hundred one".