Base | Representation |
---|---|
bin | 11110010001001011110101… |
… | …111011100101111101100010 |
3 | 122110100101000221010001002012 |
4 | 132101023311323211331202 |
5 | 114422034024124142010 |
6 | 1151043320531552522 |
7 | 40016525513255051 |
oct | 3621136573457542 |
9 | 573311027101065 |
10 | 133122342412130 |
11 | 39464960887a15 |
12 | 12b2000315b742 |
13 | 59384c9674016 |
14 | 24c322754a398 |
15 | 105cc3e741005 |
hex | 7912f5ee5f62 |
133122342412130 has 32 divisors (see below), whose sum is σ = 240487468285680. Its totient is φ = 53056217825280.
The previous prime is 133122342412121. The next prime is 133122342412153. The reversal of 133122342412130 is 31214243221331.
It can be written as a sum of positive squares in 8 ways, for example, as 57141187154041 + 75981155258089 = 7559179^2 + 8716717^2 .
It is a super-2 number, since 2×1331223424121302 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 576069410 + ... + 576300450.
Almost surely, 2133122342412130 is an apocalyptic number.
133122342412130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133122342412130 is a deficient number, since it is larger than the sum of its proper divisors (107365125873550).
133122342412130 is a wasteful number, since it uses less digits than its factorization.
133122342412130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 439334.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 133122342412130 its reverse (31214243221331), we get a palindrome (164336585633461).
The spelling of 133122342412130 in words is "one hundred thirty-three trillion, one hundred twenty-two billion, three hundred forty-two million, four hundred twelve thousand, one hundred thirty".
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