Base | Representation |
---|---|
bin | 1100000110111000100110… |
… | …1110100101110000001001 |
3 | 1202010122200001012110221201 |
4 | 3001232021232211300021 |
5 | 3221102311032422103 |
6 | 44151345544104201 |
7 | 2542535015605303 |
oct | 301561156456011 |
9 | 52118601173851 |
10 | 13312414342153 |
11 | 4272843929aa3 |
12 | 15b0050765061 |
13 | 7574807421c4 |
14 | 340477c00973 |
15 | 181446b5e51d |
hex | c1b89ba5c09 |
13312414342153 has 2 divisors, whose sum is σ = 13312414342154. Its totient is φ = 13312414342152.
The previous prime is 13312414342091. The next prime is 13312414342193. The reversal of 13312414342153 is 35124341421331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7085328301584 + 6227086040569 = 2661828^2 + 2495413^2 .
It is an emirp because it is prime and its reverse (35124341421331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13312414342153 - 213 = 13312414333961 is a prime.
It is not a weakly prime, because it can be changed into another prime (13312414342193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656207171076 + 6656207171077.
It is an arithmetic number, because the mean of its divisors is an integer number (6656207171077).
Almost surely, 213312414342153 is an apocalyptic number.
It is an amenable number.
13312414342153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312414342153 is an equidigital number, since it uses as much as digits as its factorization.
13312414342153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 37.
Adding to 13312414342153 its reverse (35124341421331), we get a palindrome (48436755763484).
The spelling of 13312414342153 in words is "thirteen trillion, three hundred twelve billion, four hundred fourteen million, three hundred forty-two thousand, one hundred fifty-three".
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