Base | Representation |
---|---|
bin | 10011010111110100001… |
… | …110000100101101000011 |
3 | 11201021011120002220012021 |
4 | 103113310032010231003 |
5 | 133302341002140301 |
6 | 2455321512542311 |
7 | 165115265130016 |
oct | 23276416045503 |
9 | 4637146086167 |
10 | 1331242224451 |
11 | 4736385918a7 |
12 | 1960063b1997 |
13 | 986c6948b99 |
14 | 4860a99537d |
15 | 24966b2a8a1 |
hex | 135f4384b43 |
1331242224451 has 2 divisors, whose sum is σ = 1331242224452. Its totient is φ = 1331242224450.
The previous prime is 1331242224443. The next prime is 1331242224523. The reversal of 1331242224451 is 1544222421331.
It is a weak prime.
It is an emirp because it is prime and its reverse (1544222421331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1331242224451 - 23 = 1331242224443 is a prime.
It is a super-2 number, since 2×13312422244512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1331242224401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665621112225 + 665621112226.
It is an arithmetic number, because the mean of its divisors is an integer number (665621112226).
Almost surely, 21331242224451 is an apocalyptic number.
1331242224451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331242224451 is an equidigital number, since it uses as much as digits as its factorization.
1331242224451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46080, while the sum is 34.
Adding to 1331242224451 its reverse (1544222421331), we get a palindrome (2875464645782).
The spelling of 1331242224451 in words is "one trillion, three hundred thirty-one billion, two hundred forty-two million, two hundred twenty-four thousand, four hundred fifty-one".
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