Base | Representation |
---|---|
bin | 10011010111110100010… |
… | …101110000111001000011 |
3 | 11201021011200220022121221 |
4 | 103113310111300321003 |
5 | 133302342011143301 |
6 | 2455322024055511 |
7 | 165115321224406 |
oct | 23276425607103 |
9 | 4637150808557 |
10 | 1331244240451 |
11 | 473639739514 |
12 | 196007004597 |
13 | 986c71a3698 |
14 | 4860ad5bd3d |
15 | 24966dc7da1 |
hex | 135f4570e43 |
1331244240451 has 2 divisors, whose sum is σ = 1331244240452. Its totient is φ = 1331244240450.
The previous prime is 1331244240433. The next prime is 1331244240511. The reversal of 1331244240451 is 1540424421331.
It is a weak prime.
It is an emirp because it is prime and its reverse (1540424421331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1331244240451 - 219 = 1331243716163 is a prime.
It is a super-2 number, since 2×13312442404512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1331244280451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665622120225 + 665622120226.
It is an arithmetic number, because the mean of its divisors is an integer number (665622120226).
Almost surely, 21331244240451 is an apocalyptic number.
1331244240451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331244240451 is an equidigital number, since it uses as much as digits as its factorization.
1331244240451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 1331244240451 its reverse (1540424421331), we get a palindrome (2871668661782).
The spelling of 1331244240451 in words is "one trillion, three hundred thirty-one billion, two hundred forty-four million, two hundred forty thousand, four hundred fifty-one".
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