1331252120041 has 2 divisors, whose sum is σ = 1331252120042. Its totient is φ = 1331252120040.

The previous prime is 1331252120017. The next prime is 1331252120089. The reversal of 1331252120041 is 1400212521331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1315847586816 + 15404533225 = 1147104^2 + 124115^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1331252120041 is a prime.

It is a super-2 number, since 2×1331252120041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1331252119988 and 1331252120015.

It is not a weakly prime, because it can be changed into another prime (1331252120741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665626060020 + 665626060021.

It is an arithmetic number, because the mean of its divisors is an integer number (665626060021).

Almost surely, 2^{1331252120041} is an apocalyptic number.

It is an amenable number.

1331252120041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331252120041 is an equidigital number, since it uses as much as digits as its factorization.

1331252120041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1331252120041 its reverse (1400212521331), we get a palindrome (2731464641372).

The spelling of 1331252120041 in words is "one trillion, three hundred thirty-one billion, two hundred fifty-two million, one hundred twenty thousand, forty-one".