1331255304241 has 4 divisors (see below), whose sum is σ = 1331615983984. Its totient is φ = 1330894624500.

The previous prime is 1331255304149. The next prime is 1331255304257. The reversal of 1331255304241 is 1424035521331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331255304241 - 2¹⁵ = 1331255271473 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331255304197 and 1331255304206.

It is not an unprimeable number, because it can be changed into a prime (1331255304341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180334335 + ... + 180341716.

It is an arithmetic number, because the mean of its divisors is an integer number (332903995996).

Almost surely, 2^{1331255304241} is an apocalyptic number.

It is an amenable number.

1331255304241 is a deficient number, since it is larger than the sum of its proper divisors (360679743).

1331255304241 is an equidigital number, since it uses as much as digits as its factorization.

1331255304241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 360679742.

The product of its (nonzero) digits is 43200, while the sum is 34.

The spelling of 1331255304241 in words is "one trillion, three hundred thirty-one billion, two hundred fifty-five million, three hundred four thousand, two hundred forty-one".