Base | Representation |
---|---|
bin | 1100000110111001100111… |
… | …0000101100101011111011 |
3 | 1202010200100210100111022122 |
4 | 3001232121300230223323 |
5 | 3221103333413032144 |
6 | 44151432353311455 |
7 | 2542544463143303 |
oct | 301563160545373 |
9 | 52120323314278 |
10 | 13312683330299 |
11 | 4272971751851 |
12 | 15b010686558b |
13 | 7574c43a25a2 |
14 | 3404a1820603 |
15 | 1814605947ee |
hex | c1b99c2cafb |
13312683330299 has 2 divisors, whose sum is σ = 13312683330300. Its totient is φ = 13312683330298.
The previous prime is 13312683330277. The next prime is 13312683330389. The reversal of 13312683330299 is 99203338621331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13312683330299 - 212 = 13312683326203 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13312683330299.
It is not a weakly prime, because it can be changed into another prime (13312683330239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656341665149 + 6656341665150.
It is an arithmetic number, because the mean of its divisors is an integer number (6656341665150).
Almost surely, 213312683330299 is an apocalyptic number.
13312683330299 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312683330299 is an equidigital number, since it uses as much as digits as its factorization.
13312683330299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3779136, while the sum is 53.
The spelling of 13312683330299 in words is "thirteen trillion, three hundred twelve billion, six hundred eighty-three million, three hundred thirty thousand, two hundred ninety-nine".
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