Base | Representation |
---|---|
bin | 11110010001010010111111… |
… | …010010011111101011001011 |
3 | 122110101002211200120112200120 |
4 | 132101102333102133223023 |
5 | 114422200232443302103 |
6 | 1151051030155034323 |
7 | 40020216615311100 |
oct | 3621227722375313 |
9 | 573332750515616 |
10 | 133130015603403 |
11 | 39468139130105 |
12 | 12b215a4a3b9a3 |
13 | 5939150290aa0 |
14 | 24c3754662aa7 |
15 | 105d03d1d4253 |
hex | 7914bf49facb |
133130015603403 has 96 divisors (see below), whose sum is σ = 223330267722240. Its totient is φ = 69920149178880.
The previous prime is 133130015603399. The next prime is 133130015603447. The reversal of 133130015603403 is 304306510031331.
It is not a de Polignac number, because 133130015603403 - 22 = 133130015603399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133130015603203) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 417009826 + ... + 417328952.
It is an arithmetic number, because the mean of its divisors is an integer number (2326356955440).
Almost surely, 2133130015603403 is an apocalyptic number.
133130015603403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133130015603403 is a deficient number, since it is larger than the sum of its proper divisors (90200252118837).
133130015603403 is a wasteful number, since it uses less digits than its factorization.
133130015603403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 320097 (or 320090 counting only the distinct ones).
The product of its (nonzero) digits is 29160, while the sum is 33.
Adding to 133130015603403 its reverse (304306510031331), we get a palindrome (437436525634734).
The spelling of 133130015603403 in words is "one hundred thirty-three trillion, one hundred thirty billion, fifteen million, six hundred three thousand, four hundred three".
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