Base | Representation |
---|---|
bin | 10011010111110111101… |
… | …011010110100101101011 |
3 | 11201021022121020221221122 |
4 | 103113313223112211223 |
5 | 133303000324402111 |
6 | 2455331344125455 |
7 | 165116601153614 |
oct | 23276753264553 |
9 | 4637277227848 |
10 | 1331300231531 |
11 | 473668301436 |
12 | 19602190688b |
13 | 987059789ba |
14 | 48614574c0b |
15 | 2496bc87cdb |
hex | 135f7ad696b |
1331300231531 has 2 divisors, whose sum is σ = 1331300231532. Its totient is φ = 1331300231530.
The previous prime is 1331300231489. The next prime is 1331300231609. The reversal of 1331300231531 is 1351320031331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1331300231531 - 230 = 1330226489707 is a prime.
It is a super-2 number, since 2×13313002315312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1331300231531.
It is not a weakly prime, because it can be changed into another prime (1331300231231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665650115765 + 665650115766.
It is an arithmetic number, because the mean of its divisors is an integer number (665650115766).
Almost surely, 21331300231531 is an apocalyptic number.
1331300231531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331300231531 is an equidigital number, since it uses as much as digits as its factorization.
1331300231531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2430, while the sum is 26.
Adding to 1331300231531 its reverse (1351320031331), we get a palindrome (2682620262862).
The spelling of 1331300231531 in words is "one trillion, three hundred thirty-one billion, three hundred million, two hundred thirty-one thousand, five hundred thirty-one".
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