Base | Representation |
---|---|
bin | 11110010001010011010110… |
… | …011100001110101101100010 |
3 | 122110101010211202110201122002 |
4 | 132101103112130032231202 |
5 | 114422202031413000310 |
6 | 1151051132512244002 |
7 | 40020232343015036 |
oct | 3621232634165542 |
9 | 573333752421562 |
10 | 133130404031330 |
11 | 39468318411822 |
12 | 12b21692b40602 |
13 | 59391b28b00b4 |
14 | 24c37900941c6 |
15 | 105d06235dda5 |
hex | 7914d670eb62 |
133130404031330 has 32 divisors (see below), whose sum is σ = 252258633149760. Its totient is φ = 50447105899200.
The previous prime is 133130404031321. The next prime is 133130404031341. The reversal of 133130404031330 is 33130404031331.
It is a junction number, because it is equal to n+sod(n) for n = 133130404031293 and 133130404031302.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11881589 + ... + 20184968.
It is an arithmetic number, because the mean of its divisors is an integer number (7883082285930).
Almost surely, 2133130404031330 is an apocalyptic number.
133130404031330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133130404031330 is a deficient number, since it is larger than the sum of its proper divisors (119128229118430).
133130404031330 is a wasteful number, since it uses less digits than its factorization.
133130404031330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32088434.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 133130404031330 its reverse (33130404031331), we get a palindrome (166260808062661).
Subtracting from 133130404031330 its reverse (33130404031331), we obtain a palindrome (99999999999999).
The spelling of 133130404031330 in words is "one hundred thirty-three trillion, one hundred thirty billion, four hundred four million, thirty-one thousand, three hundred thirty".
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