Base | Representation |
---|---|
bin | 11110010001010011010111… |
… | …011110001010001010011001 |
3 | 122110101010212221222210021102 |
4 | 132101103113132022022121 |
5 | 114422202100324023301 |
6 | 1151051134330521145 |
7 | 40020232642636313 |
oct | 3621232736121231 |
9 | 573333787883242 |
10 | 133130421314201 |
11 | 39468327146693 |
12 | 12b216988961b5 |
13 | 59391b635184c |
14 | 24c37924b27b3 |
15 | 105d063b24b6b |
hex | 7914d778a299 |
133130421314201 has 2 divisors, whose sum is σ = 133130421314202. Its totient is φ = 133130421314200.
The previous prime is 133130421314147. The next prime is 133130421314257. The reversal of 133130421314201 is 102413124031331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84609458755600 + 48520962558601 = 9198340^2 + 6965699^2 .
It is a cyclic number.
It is not a de Polignac number, because 133130421314201 - 214 = 133130421297817 is a prime.
It is not a weakly prime, because it can be changed into another prime (133130421316201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66565210657100 + 66565210657101.
It is an arithmetic number, because the mean of its divisors is an integer number (66565210657101).
Almost surely, 2133130421314201 is an apocalyptic number.
It is an amenable number.
133130421314201 is a deficient number, since it is larger than the sum of its proper divisors (1).
133130421314201 is an equidigital number, since it uses as much as digits as its factorization.
133130421314201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 133130421314201 its reverse (102413124031331), we get a palindrome (235543545345532).
The spelling of 133130421314201 in words is "one hundred thirty-three trillion, one hundred thirty billion, four hundred twenty-one million, three hundred fourteen thousand, two hundred one".
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