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1331305153 is a prime number
BaseRepresentation
bin100111101011010…
…0001101011000001
310102210002022100021
41033112201223001
510211303231103
6340034253441
744663623063
oct11726415301
93383068307
101331305153
1162353a2a2
12311a27281
13182a79039
14c8b4d733
157bd25bbd
hex4f5a1ac1

1331305153 has 2 divisors, whose sum is σ = 1331305154. Its totient is φ = 1331305152.

The previous prime is 1331305147. The next prime is 1331305187. The reversal of 1331305153 is 3515031331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 840594049 + 490711104 = 28993^2 + 22152^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331305153 - 213 = 1331296961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1331305253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665652576 + 665652577.

It is an arithmetic number, because the mean of its divisors is an integer number (665652577).

Almost surely, 21331305153 is an apocalyptic number.

It is an amenable number.

1331305153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331305153 is an equidigital number, since it uses as much as digits as its factorization.

1331305153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025, while the sum is 25.

The square root of 1331305153 is about 36487.0545947463. The cubic root of 1331305153 is about 1100.0840577638.

Adding to 1331305153 its reverse (3515031331), we get a palindrome (4846336484).

The spelling of 1331305153 in words is "one billion, three hundred thirty-one million, three hundred five thousand, one hundred fifty-three".