Base | Representation |
---|---|
bin | 1100000110111011010010… |
… | …0000010100000110011010 |
3 | 1202010201112001122022001020 |
4 | 3001232310200110012122 |
5 | 3221110243244120442 |
6 | 44151545102303310 |
7 | 2542561552015014 |
oct | 301566440240632 |
9 | 52121461568036 |
10 | 13313132020122 |
11 | 4273081a53090 |
12 | 15b0210b87b36 |
13 | 757566330b1c |
14 | 34050525b1b4 |
15 | 181489b749ec |
hex | c1bb481419a |
13313132020122 has 16 divisors (see below), whose sum is σ = 29046833498592. Its totient is φ = 4034282430320.
The previous prime is 13313132020121. The next prime is 13313132020171. The reversal of 13313132020122 is 22102023131331.
It is a super-2 number, since 2×133131320201222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13313132020092 and 13313132020101.
It is not an unprimeable number, because it can be changed into a prime (13313132020121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100857060693 + ... + 100857060824.
It is an arithmetic number, because the mean of its divisors is an integer number (1815427093662).
Almost surely, 213313132020122 is an apocalyptic number.
13313132020122 is an abundant number, since it is smaller than the sum of its proper divisors (15733701478470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13313132020122 is a wasteful number, since it uses less digits than its factorization.
13313132020122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201714121533.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13313132020122 its reverse (22102023131331), we get a palindrome (35415155151453).
The spelling of 13313132020122 in words is "thirteen trillion, three hundred thirteen billion, one hundred thirty-two million, twenty thousand, one hundred twenty-two".
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