Base | Representation |
---|---|
bin | 10011010111111000111… |
… | …111001111001101011001 |
3 | 11201021101010122011101021 |
4 | 103113320333033031121 |
5 | 133303021442041101 |
6 | 2455333451322441 |
7 | 165120256111204 |
oct | 23277077171531 |
9 | 4637333564337 |
10 | 1331322221401 |
11 | 473679760787 |
12 | 196029150421 |
13 | 9870a3a7a63 |
14 | 4861745a93b |
15 | 2496db7d5a1 |
hex | 135f8fcf359 |
1331322221401 has 2 divisors, whose sum is σ = 1331322221402. Its totient is φ = 1331322221400.
The previous prime is 1331322221377. The next prime is 1331322221443. The reversal of 1331322221401 is 1041222231331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1242112479001 + 89209742400 = 1114501^2 + 298680^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331322221401 - 219 = 1331321697113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1331328221401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665661110700 + 665661110701.
It is an arithmetic number, because the mean of its divisors is an integer number (665661110701).
Almost surely, 21331322221401 is an apocalyptic number.
It is an amenable number.
1331322221401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331322221401 is an equidigital number, since it uses as much as digits as its factorization.
1331322221401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1331322221401 its reverse (1041222231331), we get a palindrome (2372544452732).
The spelling of 1331322221401 in words is "one trillion, three hundred thirty-one billion, three hundred twenty-two million, two hundred twenty-one thousand, four hundred one".
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