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1331331211993 is a prime number
BaseRepresentation
bin10011010111111001100…
…001100010001011011001
311201021101202112221011011
4103113321201202023121
5133303031242240433
62455334412133521
7165120425404636
oct23277141421331
94637352487134
101331331211993
11473683841522
121960301672a1
139870c205033
144861871b18d
152496e8573cd
hex135f98622d9

1331331211993 has 2 divisors, whose sum is σ = 1331331211994. Its totient is φ = 1331331211992.

The previous prime is 1331331211979. The next prime is 1331331212129. The reversal of 1331331211993 is 3991121331331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1283616489024 + 47714722969 = 1132968^2 + 218437^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1331331211993 is a prime.

It is a super-3 number, since 3×13313312119933 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1331331211493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665665605996 + 665665605997.

It is an arithmetic number, because the mean of its divisors is an integer number (665665605997).

Almost surely, 21331331211993 is an apocalyptic number.

It is an amenable number.

1331331211993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331331211993 is an equidigital number, since it uses as much as digits as its factorization.

1331331211993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 39366, while the sum is 40.

The spelling of 1331331211993 in words is "one trillion, three hundred thirty-one billion, three hundred thirty-one million, two hundred eleven thousand, nine hundred ninety-three".