Base | Representation |
---|---|
bin | 10011010111111001100… |
… | …001100010001011011001 |
3 | 11201021101202112221011011 |
4 | 103113321201202023121 |
5 | 133303031242240433 |
6 | 2455334412133521 |
7 | 165120425404636 |
oct | 23277141421331 |
9 | 4637352487134 |
10 | 1331331211993 |
11 | 473683841522 |
12 | 1960301672a1 |
13 | 9870c205033 |
14 | 4861871b18d |
15 | 2496e8573cd |
hex | 135f98622d9 |
1331331211993 has 2 divisors, whose sum is σ = 1331331211994. Its totient is φ = 1331331211992.
The previous prime is 1331331211979. The next prime is 1331331212129. The reversal of 1331331211993 is 3991121331331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1283616489024 + 47714722969 = 1132968^2 + 218437^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331331211993 is a prime.
It is a super-3 number, since 3×13313312119933 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1331331211493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665665605996 + 665665605997.
It is an arithmetic number, because the mean of its divisors is an integer number (665665605997).
Almost surely, 21331331211993 is an apocalyptic number.
It is an amenable number.
1331331211993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331331211993 is an equidigital number, since it uses as much as digits as its factorization.
1331331211993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 39366, while the sum is 40.
The spelling of 1331331211993 in words is "one trillion, three hundred thirty-one billion, three hundred thirty-one million, two hundred eleven thousand, nine hundred ninety-three".
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